1 #include <iostream>
   2 #include <sstream>
   3 #include <string>
   4 #include <algorithm>
   5 #include <vector>
   6 #include <cmath>
   7 using namespace std;
   8 
   9 #define GI ({int _t; scanf("%d", &_t); _t;})
  10 #define FOR(i, a, b) for (int i=a; i<b; i++)
  11 #define REP(i, a) FOR(i, 0, a)
  12 template<class T> string toString(T n){ostringstream ost;ost<<n;ost.flush();return ost.str();}
  13 int toInt(string s){int r=0;istringstream sin(s);sin>>r;return r;}
  14 #define DBG(x) cout << #x << "::" << x << endl;
  15 #define DBGV(_v) { REP(_i, _v.size()) { cout << _v[_i] << "\t";} cout << endl;}
  16 
  17 
  18 int main() {
  19 	long double ax, ay, bx, by, cx, cy;
  20 	bool first = true;
  21 	while (cin >> ax >> ay >> bx >> by >> cx >> cy) {
  22 		//if (first == false) printf("\n");
  23 		first = false;
  24 		//cout << ax << "\t" << ay << "\t" << bx << "\t" << by << "\t" << cx << "\t" << cy << endl;
  25 		if (ax == bx) {
  26 			swap(bx, cx); swap(by, cy);
  27 		}
  28 		else if (cx == bx) {
  29 			swap(bx, ax); swap(by, ay);
  30 		}
  31 		//cout << ax << "\t" << ay << "\t" << bx << "\t" << by << "\t" << cx << "\t" << cy << endl;
  32 		long double ma = (ay-by)/(ax-bx);
  33 		long double mb = (cy-by)/(cx-bx);
  34 		//DBG(ma); DBG(mb);
  35 		long double x = (ma*mb*(ay-cy)+mb*(ax+bx)-ma*(bx+cx))/(2*(mb-ma));
  36 		long double y = (mb*(by+cy)+(cx-ax)-ma*(ay+by))/(2*(mb-ma));
  37 		long double r = sqrt((x-ax)*(x-ax)+(y-ay)*(y-ay));
  38 		long double c = -2*x;
  39 		long double d = -2*y;
  40 		long double e = x*x+y*y-r*r;
  41 		if (fabs(x)>=0 && fabs(y)>=0) {
  42 			printf("(x %s %0.3Lf)^2 + (y %s %0.3Lf)^2 = %0.3Lf^2\n", (x>0?"-":"+"), fabs(x), (y>0?"-":"+"), fabs(y), r);
  43 			printf("x^2 + y^2 %s %0.3Lfx %s %0.3Lfy %s %0.3Lf = 0\n", (c>=0?"+":"-"), fabs(c), (d>=0?"+":"-"), fabs(d), (e>=0?"+":"-"), fabs(e));
  44 		}
  45 		else if (fabs(x)>0) {
  46 			printf("(x %s %0.3Lf)^2 + y^2 = %0.3Lf^2\n", (x>=0?"-":"+"), fabs(x), r);
  47 			printf("x^2 + y^2 %s %0.3Lfx %s %0.3Lf = 0\n", (c>=0?"+":"-"), fabs(c), (e>=0?"+":"-"), fabs(e));
  48 		}
  49 		else if (fabs(y)>0) {
  50 			printf("x^2 + (y %s %0.3Lf)^2 = %0.3Lf^2\n", (y>=0?"-":"+"), fabs(y), r);
  51 			printf("x^2 + y^2 %s %0.3Lfy %s %0.3Lf = 0\n", (d>=0?"+":"-"), fabs(d), (e>=0?"+":"-"), fabs(e));
  52 		}
  53 		printf("\n");
  54 		//cout << x <<"\t" << y << endl;
  55 	}
  56 	return 0;
  57 }